Protective grounds must be able to carry what to effectively trip out the circuit?

To effectively trip out the circuit, protective grounds must be capable of carrying volt current. This occurs because when there is a fault in the electrical system, such as a short circuit, the protective grounding system needs to allow for fault current to flow through it. This flow helps to ensure that protective devices, like circuit breakers or fuses, can detect the fault condition and operate correctly to disconnect the faulty segment from the power supply.

When the fault current passes through protective grounds, it creates a voltage differential that triggers these devices to trip. This process is crucial for preventing equipment damage and ensuring safety by reducing the risk of electric shock or fire. Thus, the capacity to carry volt current is essential for grounding systems to function as intended in protecting both personnel and equipment.